So this new ice hockey or in Disney momentum, there's Hockey Park is moving to the left. Now let's notice over here that this philosophy it's negative because the force moves it to the left to the leftists. So if I want to find the last year, I divided by the Mass 60 and this velocity gives me a value off negative 0.75. Your 0.48 plus negative 0.6 Give us a value off negative zero point Well, kilograms made her sober second. I remember that my initial momentum ISS at at time zero which it's this. P one this new momentum and we define it as B zero, plus the change of moment. So let's find the change of momentum, as we did previously as force, which in this case is native 12 times the time of contact 120.5 Give us about off point negative. Now for the second scenario, we have ah force that it's been applied to it left. And since I know that the ice hockey was moving to the right, I can be sure that this velocity is to the right 10.81 12 m over second to the right. Now notice that the force that it's been applied on the first case is to the right. Therefore, if I want to find velocity, I can divide the momentum by the mass, which in this case, is 0.16. Momentum is the same as mass times velocity. This is my initial momentum before they hit it so I can plug in here My new values of 0.48 US 1.25. So p zero I can calculate from my initial values of the mask, which is 0.16 times three. So P one is the go to P zero, which is initial momentum before the hit, plus the momentum given after the hit. ![]() So let's call this new momentum once that it has been hit sp one. Now this one is also the same as my change in momentum from the left hand side of my equation. This will give us a value of one point 20 life programs. So this one is sick or to the 25 Newtons I have 13 or five is pretty here 25 0.75. So first, let's find the right hand side of this equation.įirst times time. ![]() The formula that we're going to use today is the change of momentum equal to force times the change in time, the time of country. And the question on this problem asked to find the velocity when a force has been applied into scenarios when the force has been applied to the right 4.35 seconds and when the force has been applied to the left with a magnitude of negative chilled Newton's. Oh, for this problem, we have an ice hockey pock initially moving at 3 m per second, which has a mass of 0.16 kg.
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